Solve x+1/3p-20=0

$$x + \frac { 1 } { 3 } p - 20 = 0$$

Solve for p

$$p=60-3x$$

Steps for Solving Linear Equation

Subtract x from both sides. Anything subtracted from zero gives its negation.

$$\frac{1}{3}p-20=-x$$

Add 20 to both sides.

$$\frac{1}{3}p=-x+20$$

The equation is in standard form.

$$\frac{1}{3}p=20-x$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}p}{\frac{1}{3}}=\frac{20-x}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$p=\frac{20-x}{\frac{1}{3}}$$

Divide -x+20 by \frac{1}{3} by multiplying -x+20 by the reciprocal of \frac{1}{3}.

$$p=60-3x$$

Solve for x

$$x=-\frac{p}{3}+20$$

Solution Steps

Subtract \frac{1}{3}p from both sides. Anything subtracted from zero gives its negation.

$$x-20=-\frac{1}{3}p$$

Add 20 to both sides.

$$x=-\frac{1}{3}p+20$$