Factor
\left(w+4\right)\left(w^{2}-4w+16\right)
Evaluate
w^{3}+64
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\left(w+4\right)\left(w^{2}-4w+16\right)
Rewrite w^{3}+64 as w^{3}+4^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right). Polynomial w^{2}-4w+16 is not factored since it does not have any rational roots.
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