Solve w^2=144

$$w ^ { 2 } = 144$$

Solve for w

$$w=12$$

$$w=-12$$

Steps Using Difference of Squares

Subtract 144 from both sides.

$$w^{2}-144=0$$

Consider w^{2}-144. Rewrite w^{2}-144 as w^{2}-12^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(w-12\right)\left(w+12\right)=0$$

To find equation solutions, solve w-12=0 and w+12=0.

$$w=12 w=-12$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$w=12 w=-12$$

Steps Using the Quadratic Formula

Subtract 144 from both sides.

$$w^{2}-144=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -144 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$w=\frac{0±\sqrt{0^{2}-4\left(-144\right)}}{2}$$

Square 0.

$$w=\frac{0±\sqrt{-4\left(-144\right)}}{2}$$

Multiply -4 times -144.

$$w=\frac{0±\sqrt{576}}{2}$$

Take the square root of 576.

$$w=\frac{0±24}{2}$$

Now solve the equation w=\frac{0±24}{2} when ± is plus. Divide 24 by 2.

$$w=12$$

Now solve the equation w=\frac{0±24}{2} when ± is minus. Divide -24 by 2.

$$w=-12$$

The equation is now solved.

$$w=12 w=-12$$