Solve v^2=-16

$$v ^ { 2 } = - 16$$

Solve for v

$$v=-4i$$

$$v=4i$$

Steps by Finding Square Root

The equation is now solved.

$$v=4i v=-4i$$

Steps Using the Quadratic Formula

Add 16 to both sides.

$$v^{2}+16=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 16 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$v=\frac{0±\sqrt{0^{2}-4\times 16}}{2}$$

Square 0.

$$v=\frac{0±\sqrt{-4\times 16}}{2}$$

Multiply -4 times 16.

$$v=\frac{0±\sqrt{-64}}{2}$$

Take the square root of -64.

$$v=\frac{0±8i}{2}$$

Now solve the equation v=\frac{0±8i}{2} when ± is plus.

$$v=4i$$

Now solve the equation v=\frac{0±8i}{2} when ± is minus.

$$v=-4i$$

The equation is now solved.

$$v=4i v=-4i$$