Solve for a
a=\frac{3b}{2}-\frac{v}{2}+1
Solve for b
b=\frac{v+2a-2}{3}
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3b-2a+2=v
Swap sides so that all variable terms are on the left hand side.
-2a+2=v-3b
Subtract 3b from both sides.
-2a=v-3b-2
Subtract 2 from both sides.
\frac{-2a}{-2}=\frac{v-3b-2}{-2}
Divide both sides by -2.
a=\frac{v-3b-2}{-2}
Dividing by -2 undoes the multiplication by -2.
a=\frac{3b}{2}-\frac{v}{2}+1
Divide v-3b-2 by -2.
3b-2a+2=v
Swap sides so that all variable terms are on the left hand side.
3b+2=v+2a
Add 2a to both sides.
3b=v+2a-2
Subtract 2 from both sides.
\frac{3b}{3}=\frac{v+2a-2}{3}
Divide both sides by 3.
b=\frac{v+2a-2}{3}
Dividing by 3 undoes the multiplication by 3.
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Limits
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