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v=\frac{9}{8}z-\frac{1}{8}a
Divide each term of 9z-a by 8 to get \frac{9}{8}z-\frac{1}{8}a.
\frac{9}{8}z-\frac{1}{8}a=v
Swap sides so that all variable terms are on the left hand side.
-\frac{1}{8}a=v-\frac{9}{8}z
Subtract \frac{9}{8}z from both sides.
-\frac{1}{8}a=-\frac{9z}{8}+v
The equation is in standard form.
\frac{-\frac{1}{8}a}{-\frac{1}{8}}=\frac{-\frac{9z}{8}+v}{-\frac{1}{8}}
Multiply both sides by -8.
a=\frac{-\frac{9z}{8}+v}{-\frac{1}{8}}
Dividing by -\frac{1}{8} undoes the multiplication by -\frac{1}{8}.
a=9z-8v
Divide v-\frac{9z}{8} by -\frac{1}{8} by multiplying v-\frac{9z}{8} by the reciprocal of -\frac{1}{8}.
v=\frac{9}{8}z-\frac{1}{8}a
Divide each term of 9z-a by 8 to get \frac{9}{8}z-\frac{1}{8}a.