Solve v=1/t(d_{1}-d_{2})

$$v = \frac { 1 } { t } ( d _ { 1 } - d _ { 2 } )$$

Solve for d_1

$$d_{1}=tv+d_{2}$$

$$t\neq 0$$

Solution Steps

Multiply both sides of the equation by t.

$$vt=1\left(d_{1}-d_{2}\right)$$

Use the distributive property to multiply 1 by d_{1}-d_{2}.

$$vt=d_{1}-d_{2}$$

Swap sides so that all variable terms are on the left hand side.

$$d_{1}-d_{2}=vt$$

Add d_{2} to both sides.

$$d_{1}=vt+d_{2}$$

Solve for d_2

$$d_{2}=d_{1}-tv$$

$$t\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by t.

$$vt=1\left(d_{1}-d_{2}\right)$$

Use the distributive property to multiply 1 by d_{1}-d_{2}.

$$vt=d_{1}-d_{2}$$

Swap sides so that all variable terms are on the left hand side.

$$d_{1}-d_{2}=vt$$

Subtract d_{1} from both sides.

$$-d_{2}=vt-d_{1}$$

The equation is in standard form.

$$-d_{2}=tv-d_{1}$$

Divide both sides by -1.

$$\frac{-d_{2}}{-1}=\frac{tv-d_{1}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$d_{2}=\frac{tv-d_{1}}{-1}$$

Divide vt-d_{1} by -1.

$$d_{2}=d_{1}-tv$$