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u=\sqrt{5} u=-\sqrt{5}
Take the square root of both sides of the equation.
u^{2}-5=0
Subtract 5 from both sides.
u=\frac{0±\sqrt{0^{2}-4\left(-5\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
u=\frac{0±\sqrt{-4\left(-5\right)}}{2}
Square 0.
u=\frac{0±\sqrt{20}}{2}
Multiply -4 times -5.
u=\frac{0±2\sqrt{5}}{2}
Take the square root of 20.
u=\sqrt{5}
Now solve the equation u=\frac{0±2\sqrt{5}}{2} when ± is plus.
u=-\sqrt{5}
Now solve the equation u=\frac{0±2\sqrt{5}}{2} when ± is minus.
u=\sqrt{5} u=-\sqrt{5}
The equation is now solved.