Solve u+8u/2u-7

$$u + \frac { 8 u } { 2 u - 7 }$$

Evaluate

$$\frac{u\left(2u+1\right)}{2u-7}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply u times \frac{2u-7}{2u-7}.

$$\frac{u\left(2u-7\right)}{2u-7}+\frac{8u}{2u-7}$$

Since \frac{u\left(2u-7\right)}{2u-7} and \frac{8u}{2u-7} have the same denominator, add them by adding their numerators.

$$\frac{u\left(2u-7\right)+8u}{2u-7}$$

Do the multiplications in u\left(2u-7\right)+8u.

$$\frac{2u^{2}-7u+8u}{2u-7}$$

Combine like terms in 2u^{2}-7u+8u.

$$\frac{2u^{2}+u}{2u-7}$$

Factor

$$\frac{u\left(2u+1\right)}{2u-7}$$