Solve for n
n=\frac{t_{n}-1}{3}
Solve for t_n
t_{n}=3n+1
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3n+1=t_{n}
Swap sides so that all variable terms are on the left hand side.
3n=t_{n}-1
Subtract 1 from both sides.
\frac{3n}{3}=\frac{t_{n}-1}{3}
Divide both sides by 3.
n=\frac{t_{n}-1}{3}
Dividing by 3 undoes the multiplication by 3.
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