Solve for t
t=-1
t=1
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t^{2}+5t-6=0
Substitute t for t^{2}.
t=\frac{-5±\sqrt{5^{2}-4\times 1\left(-6\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 5 for b, and -6 for c in the quadratic formula.
t=\frac{-5±7}{2}
Do the calculations.
t=1 t=-6
Solve the equation t=\frac{-5±7}{2} when ± is plus and when ± is minus.
t=1 t=-1
Since t=t^{2}, the solutions are obtained by evaluating t=±\sqrt{t} for positive t.
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