Solve t^3-5t^2+3t+14/t-3

$$t ^ { 3 } - 5 t ^ { 2 } + 3 t + 14 / t - 3$$

Evaluate

$$t^{3}-5t^{2}+3t-3+\frac{14}{t}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply t^{3}-5t^{2}+3t-3 times \frac{t}{t}.

$$\frac{\left(t^{3}-5t^{2}+3t-3\right)t}{t}+\frac{14}{t}$$

Since \frac{\left(t^{3}-5t^{2}+3t-3\right)t}{t} and \frac{14}{t} have the same denominator, add them by adding their numerators.

$$\frac{\left(t^{3}-5t^{2}+3t-3\right)t+14}{t}$$

Do the multiplications in \left(t^{3}-5t^{2}+3t-3\right)t+14.

$$\frac{t^{4}-5t^{3}+3t^{2}-3t+14}{t}$$

Factor

$$\frac{t^{4}-5t^{3}+3t^{2}-3t+14}{t}$$