Solve t^2-4t+17=t^2-8t+21

$$t ^ { 2 } - 4 t + 17 = t ^ { 2 } - 8 t + 21$$

Solve for t

$$t=1$$

Steps for Solving Linear Equation

Subtract t^{2} from both sides.

$$t^{2}-4t+17-t^{2}=-8t+21$$

Combine t^{2} and -t^{2} to get 0.

$$-4t+17=-8t+21$$

Add 8t to both sides.

$$-4t+17+8t=21$$

Combine -4t and 8t to get 4t.

$$4t+17=21$$

Subtract 17 from both sides.

$$4t=21-17$$

Subtract 17 from 21 to get 4.

$$4t=4$$

Divide both sides by 4.

$$t=\frac{4}{4}$$

Divide 4 by 4 to get 1.

$$t=1$$