Solve for t
t\in \left(-\infty,-5\right)\cup \left(5,\infty\right)
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t^{2}>25
Add 25 to both sides.
t^{2}>5^{2}
Calculate the square root of 25 and get 5. Rewrite 25 as 5^{2}.
|t|>5
Inequality holds for |t|>5.
t<-5\text{; }t>5
Rewrite |t|>5 as t<-5\text{; }t>5.
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