Solve t^2=20

$$t ^ { 2 } = 20$$

Solve for t

$$t=2\sqrt{5}\approx 4.472135955$$

$$t=-2\sqrt{5}\approx -4.472135955$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$t=2\sqrt{5} t=-2\sqrt{5}$$

Steps Using the Quadratic Formula

Subtract 20 from both sides.

$$t^{2}-20=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -20 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$t=\frac{0±\sqrt{0^{2}-4\left(-20\right)}}{2}$$

Square 0.

$$t=\frac{0±\sqrt{-4\left(-20\right)}}{2}$$

Multiply -4 times -20.

$$t=\frac{0±\sqrt{80}}{2}$$

Take the square root of 80.

$$t=\frac{0±4\sqrt{5}}{2}$$

Now solve the equation t=\frac{0±4\sqrt{5}}{2} when ± is plus.

$$t=2\sqrt{5}$$

Now solve the equation t=\frac{0±4\sqrt{5}}{2} when ± is minus.

$$t=-2\sqrt{5}$$

The equation is now solved.

$$t=2\sqrt{5} t=-2\sqrt{5}$$