Solve t^2+6x+5=0

$$t ^ { 2 } + 6 x + 5 = 0$$

Solve for x

$$x=\frac{-t^{2}-5}{6}$$

Steps for Solving Linear Equation

Subtract t^{2} from both sides. Anything subtracted from zero gives its negation.

$$6x+5=-t^{2}$$

Subtract 5 from both sides.

$$6x=-t^{2}-5$$

Divide both sides by 6.

$$\frac{6x}{6}=\frac{-t^{2}-5}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x=\frac{-t^{2}-5}{6}$$

Solve for t (complex solution)

$$t=-\sqrt{-6x-5}$$

$$t=\sqrt{-6x-5}$$

Solve for t

$$t=\sqrt{-6x-5}$$

$$t=-\sqrt{-6x-5}\text{, }x\leq -\frac{5}{6}$$