Solve for k
k=\frac{t-3z}{3}
Solve for t
t=3\left(z+k\right)
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3k+3z=t
Swap sides so that all variable terms are on the left hand side.
3k=t-3z
Subtract 3z from both sides.
\frac{3k}{3}=\frac{t-3z}{3}
Divide both sides by 3.
k=\frac{t-3z}{3}
Dividing by 3 undoes the multiplication by 3.
k=\frac{t}{3}-z
Divide t-3z by 3.
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