Solve for t
t=2x+1
Solve for x
x=\frac{t-1}{2}
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t=0x^{2}+2x+1
Multiply 0 and 2 to get 0.
t=0+2x+1
Anything times zero gives zero.
t=1+2x
Add 0 and 1 to get 1.
t=0x^{2}+2x+1
Multiply 0 and 2 to get 0.
t=0+2x+1
Anything times zero gives zero.
t=1+2x
Add 0 and 1 to get 1.
1+2x=t
Swap sides so that all variable terms are on the left hand side.
2x=t-1
Subtract 1 from both sides.
\frac{2x}{2}=\frac{t-1}{2}
Divide both sides by 2.
x=\frac{t-1}{2}
Dividing by 2 undoes the multiplication by 2.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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Linear equation
y = 3x + 4
Arithmetic
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Matrix
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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