Solve for t
t=\frac{10}{49}\approx 0.204081633
Assign t
t≔\frac{10}{49}
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t=-\frac{2}{-9.8}
Multiply 2 and 1 to get 2.
t=-\frac{20}{-98}
Expand \frac{2}{-9.8} by multiplying both numerator and the denominator by 10.
t=-\left(-\frac{10}{49}\right)
Reduce the fraction \frac{20}{-98} to lowest terms by extracting and canceling out 2.
t=\frac{10}{49}
The opposite of -\frac{10}{49} is \frac{10}{49}.
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