Evaluate
\left(x-3\right)^{2}+1
Expand
x^{2}-6x+10
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x^{2}-6x+9+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
x^{2}-6x+10
Add 9 and 1 to get 10.
x^{2}-6x+9+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
x^{2}-6x+10
Add 9 and 1 to get 10.
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