Solve s^2-24r^3+4sr^2-6rs

$$s ^ { 2 } - 24 r ^ { 3 } + 4 s r ^ { 2 } - 6 r s$$

Factor

$$\left(s-6r\right)\left(4r^{2}+s\right)$$

Solution Steps

Do the grouping s^{2}-24r^{3}+4sr^{2}-6rs=\left(-24r^{3}+4sr^{2}\right)+\left(-6rs+s^{2}\right), and factor out 4r^{2} in the first and s in the second group.

$$4r^{2}\left(-6r+s\right)+s\left(-6r+s\right)$$

Factor out common term -6r+s by using distributive property.

$$\left(-6r+s\right)\left(4r^{2}+s\right)$$

Evaluate

$$\left(s-6r\right)\left(4r^{2}+s\right)$$