Solve s^2θ=41/2

$$s ^ { 2 } \theta = 4 \frac { 1 } { 2 }$$

Solve for θ

$$\theta =\frac{9}{2s^{2}}$$

$$s\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$2s^{2}\theta =4\times 2+1$$

Multiply 4 and 2 to get 8.

$$2s^{2}\theta =8+1$$

Add 8 and 1 to get 9.

$$2s^{2}\theta =9$$

Divide both sides by 2s^{2}.

$$\frac{2s^{2}\theta }{2s^{2}}=\frac{9}{2s^{2}}$$

Dividing by 2s^{2} undoes the multiplication by 2s^{2}.

$$\theta =\frac{9}{2s^{2}}$$

Solve for s (complex solution)

$$s=-\frac{3\sqrt{2}\theta ^{-\frac{1}{2}}}{2}$$

$$s=\frac{3\sqrt{2}\theta ^{-\frac{1}{2}}}{2}\text{, }\theta \neq 0$$

Solve for s

$$s=\frac{3\sqrt{\frac{2}{\theta }}}{2}$$

$$s=-\frac{3\sqrt{\frac{2}{\theta }}}{2}\text{, }\theta >0$$