Solve for g
\left\{\begin{matrix}g=\frac{2\left(tu-s\right)}{t^{2}}\text{, }&t\neq 0\\g\in \mathrm{R}\text{, }&s=0\text{ and }t=0\end{matrix}\right.
Solve for s
s=-\frac{t\left(gt-2u\right)}{2}
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ut-\frac{1}{2}gt^{2}=s
Swap sides so that all variable terms are on the left hand side.
-\frac{1}{2}gt^{2}=s-ut
Subtract ut from both sides.
\left(-\frac{t^{2}}{2}\right)g=s-tu
The equation is in standard form.
\frac{\left(-\frac{t^{2}}{2}\right)g}{-\frac{t^{2}}{2}}=\frac{s-tu}{-\frac{t^{2}}{2}}
Divide both sides by -\frac{1}{2}t^{2}.
g=\frac{s-tu}{-\frac{t^{2}}{2}}
Dividing by -\frac{1}{2}t^{2} undoes the multiplication by -\frac{1}{2}t^{2}.
g=-\frac{2\left(s-tu\right)}{t^{2}}
Divide s-tu by -\frac{1}{2}t^{2}.
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