Solve s=(2.5m/s^2)t^2.

$$s = ( 2.5 \frac { m } { s ^ { 2 } } ) t ^ { 2 } .$$

Solve for m

$$m=\frac{2s^{3}}{5t^{2}}$$

$$t\neq 0\text{ and }s\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by s^{2}.

$$ss^{2}=2.5mt^{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$s^{3}=2.5mt^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$2.5mt^{2}=s^{3}$$

The equation is in standard form.

$$\frac{5t^{2}}{2}m=s^{3}$$

Divide both sides by 2.5t^{2}.

$$\frac{2\times \frac{5t^{2}}{2}m}{5t^{2}}=\frac{2s^{3}}{5t^{2}}$$

Dividing by 2.5t^{2} undoes the multiplication by 2.5t^{2}.

$$m=\frac{2s^{3}}{5t^{2}}$$

Solve for s

$$s=\frac{\sqrt[3]{5m}\times \left(2t\right)^{\frac{2}{3}}}{2}$$

$$m\neq 0\text{ and }t\neq 0$$