Solve rx=ay+4=

$$r x = a y + 4 =$$

Solve for a

$$\left\{\begin{matrix}a=\frac{rx-4}{y}\text{, }&y\neq 0\\a\in \mathrm{R}\text{, }&r=\frac{4}{x}\text{ and }x\neq 0\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$ay+4=rx$$

Subtract 4 from both sides.

$$ay=rx-4$$

The equation is in standard form.

$$ya=rx-4$$

Divide both sides by y.

$$\frac{ya}{y}=\frac{rx-4}{y}$$

Dividing by y undoes the multiplication by y.

$$a=\frac{rx-4}{y}$$

Solve for r

$$\left\{\begin{matrix}r=\frac{ay+4}{x}\text{, }&x\neq 0\\r\in \mathrm{R}\text{, }&a=-\frac{4}{y}\text{ and }y\neq 0\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$xr=ay+4$$

Divide both sides by x.

$$\frac{xr}{x}=\frac{ay+4}{x}$$

Dividing by x undoes the multiplication by x.

$$r=\frac{ay+4}{x}$$