Solve ru1=sqrt[3]{5x-20}

$$r u 1 = \sqrt[ 3 ] { 5 x - 20 }$$

Solve for r

$$\left\{\begin{matrix}r=\frac{\sqrt[3]{5\left(x-4\right)}}{u_{1}}\text{, }&u_{1}\neq 0\\r\in \mathrm{R}\text{, }&x=4\text{ and }u_{1}=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$u_{1}r=\sqrt[3]{5x-20}$$

Divide both sides by u_{1}.

$$\frac{u_{1}r}{u_{1}}=\frac{\sqrt[3]{5x-20}}{u_{1}}$$

Dividing by u_{1} undoes the multiplication by u_{1}.

$$r=\frac{\sqrt[3]{5x-20}}{u_{1}}$$

Solve for u_1

$$\left\{\begin{matrix}u_{1}=\frac{\sqrt[3]{5\left(x-4\right)}}{r}\text{, }&r\neq 0\\u_{1}\in \mathrm{R}\text{, }&x=4\text{ and }r=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$ru_{1}=\sqrt[3]{5x-20}$$

Divide both sides by r.

$$\frac{ru_{1}}{r}=\frac{\sqrt[3]{5x-20}}{r}$$

Dividing by r undoes the multiplication by r.

$$u_{1}=\frac{\sqrt[3]{5x-20}}{r}$$