Solve for C (complex solution)
\left\{\begin{matrix}C=-\frac{x^{2}-27x-q}{rx}\text{, }&x\neq 0\text{ and }r\neq 0\\C\in \mathrm{C}\text{, }&\left(q=0\text{ and }x=0\right)\text{ or }\left(q=x\left(x-27\right)\text{ and }r=0\text{ and }x\neq 0\right)\end{matrix}\right.
Solve for C
\left\{\begin{matrix}C=-\frac{x^{2}-27x-q}{rx}\text{, }&x\neq 0\text{ and }r\neq 0\\C\in \mathrm{R}\text{, }&\left(q=0\text{ and }x=0\right)\text{ or }\left(q=x\left(x-27\right)\text{ and }r=0\text{ and }x\neq 0\right)\end{matrix}\right.
Solve for q
q=x\left(x+Cr-27\right)
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rxC=q+27x-x^{2}
The equation is in standard form.
\frac{rxC}{rx}=\frac{q+27x-x^{2}}{rx}
Divide both sides by rx.
C=\frac{q+27x-x^{2}}{rx}
Dividing by rx undoes the multiplication by rx.
rxC=q+27x-x^{2}
The equation is in standard form.
\frac{rxC}{rx}=\frac{q+27x-x^{2}}{rx}
Divide both sides by rx.
C=\frac{q+27x-x^{2}}{rx}
Dividing by rx undoes the multiplication by rx.
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