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r^{2}-22r-7=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
r=\frac{-\left(-22\right)±\sqrt{\left(-22\right)^{2}-4\left(-7\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -22 for b, and -7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
r=\frac{-\left(-22\right)±\sqrt{484-4\left(-7\right)}}{2}
Square -22.
r=\frac{-\left(-22\right)±\sqrt{484+28}}{2}
Multiply -4 times -7.
r=\frac{-\left(-22\right)±\sqrt{512}}{2}
Add 484 to 28.
r=\frac{-\left(-22\right)±16\sqrt{2}}{2}
Take the square root of 512.
r=\frac{22±16\sqrt{2}}{2}
The opposite of -22 is 22.
r=\frac{16\sqrt{2}+22}{2}
Now solve the equation r=\frac{22±16\sqrt{2}}{2} when ± is plus. Add 22 to 16\sqrt{2}.
r=8\sqrt{2}+11
Divide 22+16\sqrt{2} by 2.
r=\frac{22-16\sqrt{2}}{2}
Now solve the equation r=\frac{22±16\sqrt{2}}{2} when ± is minus. Subtract 16\sqrt{2} from 22.
r=11-8\sqrt{2}
Divide 22-16\sqrt{2} by 2.
r=8\sqrt{2}+11 r=11-8\sqrt{2}
The equation is now solved.
r^{2}-22r-7=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
r^{2}-22r-7-\left(-7\right)=-\left(-7\right)
Add 7 to both sides of the equation.
r^{2}-22r=-\left(-7\right)
Subtracting -7 from itself leaves 0.
r^{2}-22r=7
Subtract -7 from 0.
r^{2}-22r+\left(-11\right)^{2}=7+\left(-11\right)^{2}
Divide -22, the coefficient of the x term, by 2 to get -11. Then add the square of -11 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
r^{2}-22r+121=7+121
Square -11.
r^{2}-22r+121=128
Add 7 to 121.
\left(r-11\right)^{2}=128
Factor r^{2}-22r+121. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(r-11\right)^{2}}=\sqrt{128}
Take the square root of both sides of the equation.
r-11=8\sqrt{2} r-11=-8\sqrt{2}
Simplify.
r=8\sqrt{2}+11 r=11-8\sqrt{2}
Add 11 to both sides of the equation.
x ^ 2 -22x -7 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 22 rs = -7
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 11 - u s = 11 + u
Two numbers r and s sum up to 22 exactly when the average of the two numbers is \frac{1}{2}*22 = 11. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(11 - u) (11 + u) = -7
To solve for unknown quantity u, substitute these in the product equation rs = -7
121 - u^2 = -7
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -7-121 = -128
Simplify the expression by subtracting 121 on both sides
u^2 = 128 u = \pm\sqrt{128} = \pm \sqrt{128}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =11 - \sqrt{128} = -0.314 s = 11 + \sqrt{128} = 22.314
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.