Solve r>(-4)^3+3(-4)^2-6(-4)+8

$$r > ( - 4 ) ^ { 3 } + 3 ( - 4 ) ^ { 2 } - 6 ( - 4 ) + 8$$

Solve for r

$$r>16$$

Solution Steps

Calculate -4 to the power of 3 and get -64.

$$r>-64+3\left(-4\right)^{2}-6\left(-4\right)+8$$

Calculate -4 to the power of 2 and get 16.

$$r>-64+3\times 16-6\left(-4\right)+8$$

Multiply 3 and 16 to get 48.

$$r>-64+48-6\left(-4\right)+8$$

Add -64 and 48 to get -16.

$$r>-16-6\left(-4\right)+8$$

Multiply 6 and -4 to get -24.

$$r>-16-\left(-24\right)+8$$

The opposite of -24 is 24.

$$r>-16+24+8$$

Add -16 and 24 to get 8.

$$r>8+8$$

Add 8 and 8 to get 16.

$$r>16$$