Solve for r
r=\left(x+3\right)^{2}
Solve for x
x=-\left(\sqrt{r}+3\right)
x=\sqrt{r}-3\text{, }r\geq 0
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r=x^{2}+6x+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
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