Solve r=(3+b)m

$$r = ( 3 + b ) m$$

Solve for b (complex solution)

$$\left\{\begin{matrix}b=\frac{r}{m}-3\text{, }&m\neq 0\\b\in \mathrm{C}\text{, }&r=0\text{ and }m=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3+b by m.

$$r=3m+bm$$

Swap sides so that all variable terms are on the left hand side.

$$3m+bm=r$$

Subtract 3m from both sides.

$$bm=r-3m$$

The equation is in standard form.

$$mb=r-3m$$

Divide both sides by m.

$$\frac{mb}{m}=\frac{r-3m}{m}$$

Dividing by m undoes the multiplication by m.

$$b=\frac{r-3m}{m}$$

Divide r-3m by m.

$$b=\frac{r}{m}-3$$

Solve for m (complex solution)

$$\left\{\begin{matrix}m=\frac{r}{b+3}\text{, }&b\neq -3\\m\in \mathrm{C}\text{, }&r=0\text{ and }b=-3\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3+b by m.

$$r=3m+bm$$

Swap sides so that all variable terms are on the left hand side.

$$3m+bm=r$$

Combine all terms containing m.

$$\left(3+b\right)m=r$$

The equation is in standard form.

$$\left(b+3\right)m=r$$

Divide both sides by 3+b.

$$\frac{\left(b+3\right)m}{b+3}=\frac{r}{b+3}$$

Dividing by 3+b undoes the multiplication by 3+b.

$$m=\frac{r}{b+3}$$

Solve for b

$$\left\{\begin{matrix}b=\frac{r}{m}-3\text{, }&m\neq 0\\b\in \mathrm{R}\text{, }&r=0\text{ and }m=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3+b by m.

$$r=3m+bm$$

Swap sides so that all variable terms are on the left hand side.

$$3m+bm=r$$

Subtract 3m from both sides.

$$bm=r-3m$$

The equation is in standard form.

$$mb=r-3m$$

Divide both sides by m.

$$\frac{mb}{m}=\frac{r-3m}{m}$$

Dividing by m undoes the multiplication by m.

$$b=\frac{r-3m}{m}$$

Divide r-3m by m.

$$b=\frac{r}{m}-3$$

Solve for m

$$\left\{\begin{matrix}m=\frac{r}{b+3}\text{, }&b\neq -3\\m\in \mathrm{R}\text{, }&r=0\text{ and }b=-3\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3+b by m.

$$r=3m+bm$$

Swap sides so that all variable terms are on the left hand side.

$$3m+bm=r$$

Combine all terms containing m.

$$\left(3+b\right)m=r$$

The equation is in standard form.

$$\left(b+3\right)m=r$$

Divide both sides by 3+b.

$$\frac{\left(b+3\right)m}{b+3}=\frac{r}{b+3}$$

Dividing by 3+b undoes the multiplication by 3+b.

$$m=\frac{r}{b+3}$$