Solve for p
p=7r-q
Solve for q
q=7r-p
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r=\frac{1}{7}p+\frac{1}{7}q
Divide each term of p+q by 7 to get \frac{1}{7}p+\frac{1}{7}q.
\frac{1}{7}p+\frac{1}{7}q=r
Swap sides so that all variable terms are on the left hand side.
\frac{1}{7}p=r-\frac{1}{7}q
Subtract \frac{1}{7}q from both sides.
\frac{1}{7}p=-\frac{q}{7}+r
The equation is in standard form.
\frac{\frac{1}{7}p}{\frac{1}{7}}=\frac{-\frac{q}{7}+r}{\frac{1}{7}}
Multiply both sides by 7.
p=\frac{-\frac{q}{7}+r}{\frac{1}{7}}
Dividing by \frac{1}{7} undoes the multiplication by \frac{1}{7}.
p=7r-q
Divide r-\frac{q}{7} by \frac{1}{7} by multiplying r-\frac{q}{7} by the reciprocal of \frac{1}{7}.
r=\frac{1}{7}p+\frac{1}{7}q
Divide each term of p+q by 7 to get \frac{1}{7}p+\frac{1}{7}q.
\frac{1}{7}p+\frac{1}{7}q=r
Swap sides so that all variable terms are on the left hand side.
\frac{1}{7}q=r-\frac{1}{7}p
Subtract \frac{1}{7}p from both sides.
\frac{1}{7}q=-\frac{p}{7}+r
The equation is in standard form.
\frac{\frac{1}{7}q}{\frac{1}{7}}=\frac{-\frac{p}{7}+r}{\frac{1}{7}}
Multiply both sides by 7.
q=\frac{-\frac{p}{7}+r}{\frac{1}{7}}
Dividing by \frac{1}{7} undoes the multiplication by \frac{1}{7}.
q=7r-p
Divide r-\frac{p}{7} by \frac{1}{7} by multiplying r-\frac{p}{7} by the reciprocal of \frac{1}{7}.
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