Solve for a
a=r\cos(\theta )
\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\pi n_{1}+\frac{\pi }{2}
Solve for r
r=\frac{a}{\cos(\theta )}
\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\pi n_{1}+\frac{\pi }{2}
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\frac{a}{\cos(\theta )}=r
Swap sides so that all variable terms are on the left hand side.
\frac{1}{\cos(\theta )}a=r
The equation is in standard form.
\frac{\frac{1}{\cos(\theta )}a\cos(\theta )}{1}=\frac{r\cos(\theta )}{1}
Divide both sides by \left(\cos(\theta )\right)^{-1}.
a=\frac{r\cos(\theta )}{1}
Dividing by \left(\cos(\theta )\right)^{-1} undoes the multiplication by \left(\cos(\theta )\right)^{-1}.
a=r\cos(\theta )
Divide r by \left(\cos(\theta )\right)^{-1}.
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