Solve r=4p+2/3-p

$$r = \frac { 4 p + 2 } { 3 - p }$$

Solve for p

$$p=\frac{3r-2}{r+4}$$

$$r\neq -4$$

Steps for Solving Linear Equation

Variable p cannot be equal to 3 since division by zero is not defined. Multiply both sides of the equation by -p+3.

$$r\left(-p+3\right)=4p+2$$

Use the distributive property to multiply r by -p+3.

$$-rp+3r=4p+2$$

Subtract 4p from both sides.

$$-rp+3r-4p=2$$

Subtract 3r from both sides.

$$-rp-4p=2-3r$$

Combine all terms containing p.

$$\left(-r-4\right)p=2-3r$$

Divide both sides by -r-4.

$$\frac{\left(-r-4\right)p}{-r-4}=\frac{2-3r}{-r-4}$$

Dividing by -r-4 undoes the multiplication by -r-4.

$$p=\frac{2-3r}{-r-4}$$

Divide 2-3r by -r-4.

$$p=-\frac{2-3r}{r+4}$$

Variable p cannot be equal to 3.

$$p=-\frac{2-3r}{r+4}\text{, }p\neq 3$$

Solve for r

$$r=\frac{2\left(2p+1\right)}{3-p}$$

$$p\neq 3$$