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Solve for r
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r=\frac{1.5\times \frac{5}{3}r}{2.5}
Divide 10r by 6 to get \frac{5}{3}r.
r=\frac{\frac{3}{2}\times \frac{5}{3}r}{2.5}
Convert decimal number 1.5 to fraction \frac{15}{10}. Reduce the fraction \frac{15}{10} to lowest terms by extracting and canceling out 5.
r=\frac{\frac{3\times 5}{2\times 3}r}{2.5}
Multiply \frac{3}{2} times \frac{5}{3} by multiplying numerator times numerator and denominator times denominator.
r=\frac{\frac{5}{2}r}{2.5}
Cancel out 3 in both numerator and denominator.
r=r
Cancel out 2.5 and 2.5.
r-r=0
Subtract r from both sides.
0=0
Combine r and -r to get 0.
\text{true}
Compare 0 and 0.
r\in \mathrm{R}
This is true for any r.