Solve for r (complex solution)
\left\{\begin{matrix}r=-\frac{x-\epsilon }{1-u}\text{, }&u\neq 1\\r\in \mathrm{C}\text{, }&x=\epsilon \text{ and }u=1\end{matrix}\right.
Solve for u (complex solution)
\left\{\begin{matrix}u=-\frac{-x+\epsilon -r}{r}\text{, }&r\neq 0\\u\in \mathrm{C}\text{, }&r=0\text{ and }x=\epsilon \end{matrix}\right.
Solve for r
\left\{\begin{matrix}r=-\frac{x-\epsilon }{1-u}\text{, }&u\neq 1\\r\in \mathrm{R}\text{, }&x=\epsilon \text{ and }u=1\end{matrix}\right.
Solve for u
\left\{\begin{matrix}u=-\frac{-x+\epsilon -r}{r}\text{, }&r\neq 0\\u\in \mathrm{R}\text{, }&r=0\text{ and }x=\epsilon \end{matrix}\right.
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r+x-ru=\epsilon
Subtract ru from both sides.
r-ru=\epsilon -x
Subtract x from both sides.
\left(1-u\right)r=\epsilon -x
Combine all terms containing r.
\frac{\left(1-u\right)r}{1-u}=\frac{\epsilon -x}{1-u}
Divide both sides by 1-u.
r=\frac{\epsilon -x}{1-u}
Dividing by 1-u undoes the multiplication by 1-u.
ru+\epsilon =r+x
Swap sides so that all variable terms are on the left hand side.
ru=r+x-\epsilon
Subtract \epsilon from both sides.
ru=x+r-\epsilon
The equation is in standard form.
\frac{ru}{r}=\frac{x+r-\epsilon }{r}
Divide both sides by r.
u=\frac{x+r-\epsilon }{r}
Dividing by r undoes the multiplication by r.
r+x-ru=\epsilon
Subtract ru from both sides.
r-ru=\epsilon -x
Subtract x from both sides.
\left(1-u\right)r=\epsilon -x
Combine all terms containing r.
\frac{\left(1-u\right)r}{1-u}=\frac{\epsilon -x}{1-u}
Divide both sides by 1-u.
r=\frac{\epsilon -x}{1-u}
Dividing by 1-u undoes the multiplication by 1-u.
ru+\epsilon =r+x
Swap sides so that all variable terms are on the left hand side.
ru=r+x-\epsilon
Subtract \epsilon from both sides.
ru=x+r-\epsilon
The equation is in standard form.
\frac{ru}{r}=\frac{x+r-\epsilon }{r}
Divide both sides by r.
u=\frac{x+r-\epsilon }{r}
Dividing by r undoes the multiplication by r.
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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