Solve q=K(2)(3)^2/8

$$q = \frac { K ( 2 ) ( 3 ) ^ { 2 } } { 8 }$$

Solve for K

$$K=\frac{4q}{9}$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$q=\frac{K\times 2\times 9}{8}$$

Multiply 2 and 9 to get 18.

$$q=\frac{K\times 18}{8}$$

Divide K\times 18 by 8 to get K\times \left(\frac{9}{4}\right).

$$q=K\times \left(\frac{9}{4}\right)$$

Swap sides so that all variable terms are on the left hand side.

$$K\times \left(\frac{9}{4}\right)=q$$

The equation is in standard form.

$$\frac{9}{4}K=q$$

Divide both sides of the equation by \frac{9}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{9}{4}K}{\frac{9}{4}}=\frac{q}{\frac{9}{4}}$$

Dividing by \frac{9}{4} undoes the multiplication by \frac{9}{4}.

$$K=\frac{q}{\frac{9}{4}}$$

Divide q by \frac{9}{4} by multiplying q by the reciprocal of \frac{9}{4}.

$$K=\frac{4q}{9}$$

Solve for q

$$q=\frac{9K}{4}$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$q=\frac{K\times 2\times 9}{8}$$

Multiply 2 and 9 to get 18.

$$q=\frac{K\times 18}{8}$$

Divide K\times 18 by 8 to get K\times \left(\frac{9}{4}\right).

$$q=K\times \left(\frac{9}{4}\right)$$