Solve px^2+39=5r=

$$p x ^ { 2 } + 39 = 5 r =$$

Solve for p (complex solution)

$$\left\{\begin{matrix}p=-\frac{39-5r}{x^{2}}\text{, }&x\neq 0\\p\in \mathrm{C}\text{, }&r=\frac{39}{5}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 39 from both sides.

$$px^{2}=5r-39$$

The equation is in standard form.

$$x^{2}p=5r-39$$

Divide both sides by x^{2}.

$$\frac{x^{2}p}{x^{2}}=\frac{5r-39}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$p=\frac{5r-39}{x^{2}}$$

Solve for p

$$\left\{\begin{matrix}p=-\frac{39-5r}{x^{2}}\text{, }&x\neq 0\\p\in \mathrm{R}\text{, }&r=\frac{39}{5}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 39 from both sides.

$$px^{2}=5r-39$$

The equation is in standard form.

$$x^{2}p=5r-39$$

Divide both sides by x^{2}.

$$\frac{x^{2}p}{x^{2}}=\frac{5r-39}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$p=\frac{5r-39}{x^{2}}$$

Solve for r

$$r=\frac{px^{2}+39}{5}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$5r=px^{2}+39$$

Divide both sides by 5.

$$\frac{5r}{5}=\frac{px^{2}+39}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$r=\frac{px^{2}+39}{5}$$