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-4\sqrt{p}=21-p
Subtract p from both sides of the equation.
\left(-4\sqrt{p}\right)^{2}=\left(21-p\right)^{2}
Square both sides of the equation.
\left(-4\right)^{2}\left(\sqrt{p}\right)^{2}=\left(21-p\right)^{2}
Expand \left(-4\sqrt{p}\right)^{2}.
16\left(\sqrt{p}\right)^{2}=\left(21-p\right)^{2}
Calculate -4 to the power of 2 and get 16.
16p=\left(21-p\right)^{2}
Calculate \sqrt{p} to the power of 2 and get p.
16p=441-42p+p^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(21-p\right)^{2}.
16p-441=-42p+p^{2}
Subtract 441 from both sides.
16p-441+42p=p^{2}
Add 42p to both sides.
58p-441=p^{2}
Combine 16p and 42p to get 58p.
58p-441-p^{2}=0
Subtract p^{2} from both sides.
-p^{2}+58p-441=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=58 ab=-\left(-441\right)=441
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -p^{2}+ap+bp-441. To find a and b, set up a system to be solved.
1,441 3,147 7,63 9,49 21,21
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 441.
1+441=442 3+147=150 7+63=70 9+49=58 21+21=42
Calculate the sum for each pair.
a=49 b=9
The solution is the pair that gives sum 58.
\left(-p^{2}+49p\right)+\left(9p-441\right)
Rewrite -p^{2}+58p-441 as \left(-p^{2}+49p\right)+\left(9p-441\right).
-p\left(p-49\right)+9\left(p-49\right)
Factor out -p in the first and 9 in the second group.
\left(p-49\right)\left(-p+9\right)
Factor out common term p-49 by using distributive property.
p=49 p=9
To find equation solutions, solve p-49=0 and -p+9=0.
49-4\sqrt{49}=21
Substitute 49 for p in the equation p-4\sqrt{p}=21.
21=21
Simplify. The value p=49 satisfies the equation.
9-4\sqrt{9}=21
Substitute 9 for p in the equation p-4\sqrt{p}=21.
-3=21
Simplify. The value p=9 does not satisfy the equation because the left and the right hand side have opposite signs.
p=49
Equation -4\sqrt{p}=21-p has a unique solution.