Solve p(x)=-x^3/4-3

$$p ( x ) = - \frac { x ^ { 3 } } { 4 } - 3$$

Evaluate

$$-\frac{x^{3}}{4}-3$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{4}{4}.

$$-\frac{x^{3}}{4}-\frac{3\times 4}{4}$$

Since -\frac{x^{3}}{4} and \frac{3\times 4}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-x^{3}-3\times 4}{4}$$

Do the multiplications in -x^{3}-3\times 4.

$$\frac{-x^{3}-12}{4}$$

Factor

$$\frac{-x^{3}-12}{4}$$

Solution Steps

Factor out \frac{1}{4}. Polynomial -x^{3}-12 is not factored since it does not have any rational roots.

$$\frac{-x^{3}-12}{4}$$