Solve p(-3)=(-3)^3-a(-3)^2-13(-3)

$$p ( - 3 ) = ( - 3 ) ^ { 3 } - a ( - 3 ) ^ { 2 } - 13 ( - 3 )$$

Evaluate

$$12-9a$$

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$-27-a\left(-3\right)^{2}-13\left(-3\right)$$

Calculate -3 to the power of 2 and get 9.

$$-27-a\times 9-13\left(-3\right)$$

Multiply 13 and -3 to get -39.

$$-27-a\times 9-\left(-39\right)$$

The opposite of -39 is 39.

$$-27-a\times 9+39$$

Multiply -1 and 9 to get -9.

$$-27-9a+39$$

Add -27 and 39 to get 12.

$$12-9a$$

Factor

$$3\left(4-3a\right)$$

Solution Steps

Factor out 3.

$$3\left(4-3a\right)$$

Consider -9-3a+13. Multiply and combine like terms.

$$-3a+4$$

Rewrite the complete factored expression.

$$3\left(-3a+4\right)$$