Solve p(-2)=(-2)^3+3(-2)^2-5(-2)+2

$$p ( - 2 ) = ( - 2 ) ^ { 3 } + 3 ( - 2 ) ^ { 2 } - 5 ( - 2 ) + 2$$

Evaluate

$$16$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+3\left(-2\right)^{2}-5\left(-2\right)+2$$

Calculate -2 to the power of 2 and get 4.

$$-8+3\times 4-5\left(-2\right)+2$$

Multiply 3 and 4 to get 12.

$$-8+12-5\left(-2\right)+2$$

Add -8 and 12 to get 4.

$$4-5\left(-2\right)+2$$

Multiply 5 and -2 to get -10.

$$4-\left(-10\right)+2$$

The opposite of -10 is 10.

$$4+10+2$$

Add 4 and 10 to get 14.

$$14+2$$

Add 14 and 2 to get 16.

$$16$$

Factor

$$2^{4}$$