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\left(p^{2}-8q^{2}\right)\left(p^{4}+8p^{2}q^{2}+64q^{4}\right)
Rewrite p^{6}-512q^{6} as \left(p^{2}\right)^{3}-\left(8q^{2}\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).