Solve p^2=12

$$p ^ { 2 } = 12$$

Solve for p

$$p=2\sqrt{3}\approx 3.464101615$$

$$p=-2\sqrt{3}\approx -3.464101615$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$p=2\sqrt{3} p=-2\sqrt{3}$$

Steps Using the Quadratic Formula

Subtract 12 from both sides.

$$p^{2}-12=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -12 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$p=\frac{0±\sqrt{0^{2}-4\left(-12\right)}}{2}$$

Square 0.

$$p=\frac{0±\sqrt{-4\left(-12\right)}}{2}$$

Multiply -4 times -12.

$$p=\frac{0±\sqrt{48}}{2}$$

Take the square root of 48.

$$p=\frac{0±4\sqrt{3}}{2}$$

Now solve the equation p=\frac{0±4\sqrt{3}}{2} when ± is plus.

$$p=2\sqrt{3}$$

Now solve the equation p=\frac{0±4\sqrt{3}}{2} when ± is minus.

$$p=-2\sqrt{3}$$

The equation is now solved.

$$p=2\sqrt{3} p=-2\sqrt{3}$$