Solve p^2+py=1Rightarrow1

$$p ^ { 2 } + p y = 1 \Rightarrow 1$$

Solve for y

$$y=-p+\frac{1}{p}$$

$$p\neq 0$$

Steps for Solving Linear Equation

Subtract p^{2} from both sides.

$$py=1-p^{2}$$

Divide both sides by p.

$$\frac{py}{p}=\frac{1-p^{2}}{p}$$

Dividing by p undoes the multiplication by p.

$$y=\frac{1-p^{2}}{p}$$

Divide -p^{2}+1 by p.

$$y=-p+\frac{1}{p}$$

Solve for p

$$p=\frac{\sqrt{y^{2}+4}-y}{2}$$

$$p=\frac{-\sqrt{y^{2}+4}-y}{2}$$