Solve p^2+16b+50=0

$$p ^ { 2 } + 16 b + 50 = 0$$

Solve for b

$$b=-\frac{p^{2}}{16}-\frac{25}{8}$$

Steps for Solving Linear Equation

Subtract p^{2} from both sides. Anything subtracted from zero gives its negation.

$$16b+50=-p^{2}$$

Subtract 50 from both sides.

$$16b=-p^{2}-50$$

Divide both sides by 16.

$$\frac{16b}{16}=\frac{-p^{2}-50}{16}$$

Dividing by 16 undoes the multiplication by 16.

$$b=\frac{-p^{2}-50}{16}$$

Divide -p^{2}-50 by 16.

$$b=-\frac{p^{2}}{16}-\frac{25}{8}$$

Solve for p

$$p=\sqrt{-16b-50}$$

$$p=-\sqrt{-16b-50}\text{, }b\leq -\frac{25}{8}$$