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Solve for n_1
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Solve for n_2
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\sin(\theta _{1})n_{1}=n_{2}\sin(\theta _{2})
The equation is in standard form.
\frac{\sin(\theta _{1})n_{1}}{\sin(\theta _{1})}=\frac{n_{2}\sin(\theta _{2})}{\sin(\theta _{1})}
Divide both sides by \sin(\theta _{1}).
n_{1}=\frac{n_{2}\sin(\theta _{2})}{\sin(\theta _{1})}
Dividing by \sin(\theta _{1}) undoes the multiplication by \sin(\theta _{1}).
n_{2}\sin(\theta _{2})=n_{1}\sin(\theta _{1})
Swap sides so that all variable terms are on the left hand side.
\sin(\theta _{2})n_{2}=n_{1}\sin(\theta _{1})
The equation is in standard form.
\frac{\sin(\theta _{2})n_{2}}{\sin(\theta _{2})}=\frac{n_{1}\sin(\theta _{1})}{\sin(\theta _{2})}
Divide both sides by \sin(\theta _{2}).
n_{2}=\frac{n_{1}\sin(\theta _{1})}{\sin(\theta _{2})}
Dividing by \sin(\theta _{2}) undoes the multiplication by \sin(\theta _{2}).