Solve n5x+0.25=7x-0.05?

$$n 5 x + 0.25 = 7 x - 0.05 ?$$

Solve for n_5

$$n_{5}=7-\frac{3}{10x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 0.25 from both sides.

$$n_{5}x=7x-0.05-0.25$$

Subtract 0.25 from -0.05 to get -0.3.

$$n_{5}x=7x-0.3$$

The equation is in standard form.

$$xn_{5}=7x-0.3$$

Divide both sides by x.

$$\frac{xn_{5}}{x}=\frac{7x-0.3}{x}$$

Dividing by x undoes the multiplication by x.

$$n_{5}=\frac{7x-0.3}{x}$$

Divide 7x-0.3 by x.

$$n_{5}=7-\frac{3}{10x}$$

Solve for x

$$x=-\frac{3}{10\left(n_{5}-7\right)}$$

$$n_{5}\neq 7$$

Steps for Solving Linear Equation

Subtract 7x from both sides.

$$n_{5}x+0.25-7x=-0.05$$

Subtract 0.25 from both sides.

$$n_{5}x-7x=-0.05-0.25$$

Subtract 0.25 from -0.05 to get -0.3.

$$n_{5}x-7x=-0.3$$

Combine all terms containing x.

$$\left(n_{5}-7\right)x=-0.3$$

Divide both sides by n_{5}-7.

$$\frac{\left(n_{5}-7\right)x}{n_{5}-7}=-\frac{0.3}{n_{5}-7}$$

Dividing by n_{5}-7 undoes the multiplication by n_{5}-7.

$$x=-\frac{0.3}{n_{5}-7}$$

Divide -0.3 by n_{5}-7.

$$x=-\frac{3}{10\left(n_{5}-7\right)}$$