Solve ngeq[0.3*1.96/0.05]^2

$$n \geq [ \frac { 0.3 \cdot 1.96 } { 0.05 } ] ^ { 2 }$$

Solve for n

$$n\geq 138.2976$$

Solution Steps

Multiply 0.3 and 1.96 to get 0.588.

$$n\geq \left(\frac{0.588}{0.05}\right)^{2}$$

Expand \frac{0.588}{0.05} by multiplying both numerator and the denominator by 1000.

$$n\geq \left(\frac{588}{50}\right)^{2}$$

Reduce the fraction \frac{588}{50} to lowest terms by extracting and canceling out 2.

$$n\geq \left(\frac{294}{25}\right)^{2}$$

Calculate \frac{294}{25} to the power of 2 and get \frac{86436}{625}.

$$n\geq \frac{86436}{625}$$