Solve n-2/3+sqrt[4]{1/16}*149

$$n \frac { - 2 } { 3 } + \sqrt[ 4 ] { \frac { 1 } { 16 } } \cdot 149$$

Evaluate

$$-\frac{2n}{3}+\frac{149}{2}$$

Solution Steps

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$n\left(-\frac{2}{3}\right)+\sqrt[4]{\frac{1}{16}}\times 149$$

Calculate \sqrt[4]{\frac{1}{16}} and get \frac{1}{2}.

$$n\left(-\frac{2}{3}\right)+\frac{1}{2}\times 149$$

Multiply \frac{1}{2} and 149 to get \frac{149}{2}.

$$n\left(-\frac{2}{3}\right)+\frac{149}{2}$$

Factor

$$\frac{447-4n}{6}$$

Solution Steps

Factor out \frac{1}{3}.

$$\frac{-2n+\frac{447}{2}}{3}$$